### Digital Electronics Objectives Part 02

**21 . ** **none of above **Binary product is incorrect.

**22 .** **1111-111** = 1000

**23 .** ** 11111+11111=100000** is incorrect

**24 .** Binary 101010 is equivalent to decimal number** 42.**

**25 .** Decimal number 5436 when converter into 9’s complement will become** 4563.**

**26 . ** Decimal 1932 when converted into 10’s complement will become **8068.**

**27 . ** Decimal 45.15 when converted into 9’s complement will become** 54.84.**

**28 . ** Decimal 18.293 when converted into 10’s complement will become **81.707.**

** 29 .** ** 64** different binary numbers can be stored in a register consisting of six switches.

**30 .** **1000** different BCD numbers can be stored in a register containing 12 switches using an 8,4,2,1 code.

**31 .** The hexadecimal number B6C7 is equivalent to decimal number **46791.**

**32 . ** The hexadecimal number 64AC is equivalent to decimal number **25772.**

**33 . ** The hexadecimal number A492 is equivalent to decimal number** 42130.**

**34 . ** The hexadecimal number D2763 is equivalent to decimal number **862051.**

**35 .** The binary number 101101 is equal to octal number **55.**

**36 .** Binary number 1011 when converted to its 1’s complement will become** 0100.**

**37 .** Binary number 1011 when converted to its 1’s complement will become** 01100.**

**38 . ** Binary number 1011.01 when converted to its 2’s complement will become **0100.10.**

**39 . ** Binary number 1011.01 when converted to its 2’s complement will become** 00100.11.**

**40 .** The binary number 0111011011 is equivalent to decimal number **3.554.**