71 The rms value of current through the resistance will be**a. 6 A**

b. 5 A

c. 4 A

d. 3 A

72. The average value of current for the half cycle will be**a. 5.4 A**

b. 4.4 A

c. 4.0 A

d. 3.6 A

73. The power dissipated in the resistor will be

a. 0.5.k W

b. 1 k W**c. 1.8 kW**

d. 3.6 kW

74. The output voltage will be**a. 28 mV**b. 66 mV

c. 44 mV

d. 22 mV

75. If the loop has 10 turns instead of one the maximum output voltage will be

a. 1760 mV**b. 880 mV**

c. 440 mV

d. 110 mV

76. For the generator with 10 turns the instantaneous level of voltages at 5×180/4 radians from e = 0 will be

a. 0.31 V

b. 0.62 V**c. -0.62 V**

d. -0.31 V

77. In the above case the value of output voltage at 25 ms from e = 0 will be

a. 64.4 m V

b. 128.6 m V

c. 255.1 m V**d. 315.4 m V**

78. The instantaneous power dissipated in the resistor at 5.5 milli seconds from the time that the waveform commences to grow positively from zero will be**a. 0.44 W**

b. 0.66 W

c. 0.88 W

d. 1.76 W

79. The peak instantaneous power dissipated in the resistor will be

a. 3 W

b. 4.5 W**c. 6 W****d. 9 W**

80. The average power dissipated in the resistor will be**a. **1.2 W

b. 0.9 W

c. 0.6 W**d. 0.3 W**

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